P6 Math: Counters

 Gerald, Michael, and Pritam had 288 counters altogether. After Gerald gave Michael some counters, Michael had twice his original number of counters. Then Michael gave Pritam some counters and Pritam had twice his original number of counters. All the boys had an equal number of counters in the end. How many counters did Gerald have at first?

Solution: 

There are one key informations here: each boys has same number of counters at the end.

288 / 3 = 96 counters in the end for each boy.

Let's start with Pritam, he had twice his original number of counters.

2p = 96 --> p = 48, at first Pritam had 48 counters.

48 additional counters Pritam had, was given by Michael.

2m - 48 = 96 --> 2m = 144 --> m = 72, at first Michael had 72 counters

72 additional counters Michael had, was given by Gerald.

g - 72 = 96 --> g = 96 + 72 = 168, at first Gerald has 168 counters.

TO DO: create the model to visualize it.